0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The energy (E), angular momentum (L) and universal gravitational constant (G) are chosen as fundamental quantities. The dimensions of universal gravitational constant in the dimensional formula of planks constant (h) is :
  1. 0
  2. 1
  3. 1
  4. 53

A
0
B
53
C
1
D
1
Solution
Verified by Toppr

h=GαEβLγ

(ML2T2.T)=[M1L3T2]α[ML2T2]β.[ML2T]γ

[ML2T1]=Mα+β+γL3α+2β+2γT2α2βγ
α+β+γ=1
3α+2β+2γ=2
α=0=β
2α2βγ=1
γ=1
Since α=0,
G in dimensional formula for h is 0.

Was this answer helpful?
1
Similar Questions
Q1
The energy (E), angular momentum (L) and universal gravitational constant (G) are chosen as fundamental quantities. The dimensions of universal gravitational constant in the dimensional formula of planks constant (h) is :
View Solution
Q2
The energy (E), angular momentum (L) and universal gravitational constant (G) are chosen as fundamental quantities. The dimensions of universal gravitational constant in the dimensional formula of Planck's constant (h) is
View Solution
Q3
If the velocity of light C, the universal gravitational constant G, and Planck's constant h are chosen as fundamental units, the dimension of mass in this system are
View Solution
Q4
If E,M,J and G respectively denote energy, mass, angular momentum and universal gravitational constant, the quantity, which has the same dimensions as the dimensions of EJ2M5G2 is:

View Solution
Q5

If E, G, J and m represent energy, universal gravitational constant, angular momentum and mass respectively, then dimensions of EJ2m5G2 are those of:


View Solution