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Question

The energy of a particle executing simple harmonic motion is given by the equation E=Ax2+Bv2 where x is the displacement from mean position x=0 and v is the velocity of the particle at x. Find the amplitude of S.H.M.

Solution
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E=Ax2+Bv2
As we know that at max amplitude, V=0
E=Aa2
Let a be amplitude
a2=EA
|a|=EA1.

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