The energy of a particle executing simple harmonic motion is given by the equation E=Ax2+Bv2 where x is the displacement from mean position x=0 and v is the velocity of the particle at x. Find the amplitude of S.H.M.
E=Ax2+Bv2
As we know that at max amplitude, V=0
∴E=Aa2
Let a be amplitude
∴a2=EA
|a|=√EA1.