Question

# The energy released by fission from 2g of 23592U in kWh is (the energy released per fission is 200MeV):

A
4.556 x 107
B
4.556 x 104
C
4.556 x 106
D
4.556 x 105
Solution
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#### Number of atoms in 2g of 23592U=2235×NA where NA is avogadro number =2235×6.023×1023Energy per fission =200 MeVTherefore total energy (K)=2235×6.023×1023×200×106×1.6×10−19JTotal Energy in kWh=k3600×103=4.556×104kWh

2
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