The energy released per fission of a 92U235 nucleus is nearly
On fission of one nucleus of U235, the amount of energy obtained is 200 MeV. The power obtained in a reactor is 1000 kW. Number of nuclei fissioned per second in the reactor is
The energy released per fission reaction of U235 is 200 MeV. Find the energy released by the fission of 1 g of U235.
(Avogadro number, NA=6.023×1023)
If 200MeV energy is released in the fission of a single U235 nucleus, the number of fissions require per second to produce a 1 kilowatt power shall be (Given1eV=1.6×10−19J)
Assuming 200MeV of energy is released per fission of 92U235, calculate the energy released when 1kg of 92U235 undergoes complete fission. What percentage of mass of 92U235 gets converted into energy ?