The energy required to separate the typical middle mass nucleus $_{50}^{120} S n$ into its constituent nucleons is :
(Mass of $_{50}^{120} S n =$ $119.902199 a m u$ ; mass
of proton $= 1.007825 a m u$ and mass of neutron $= 1.008665 a m u$ )

Question

The energy required to separate the typical middle mass nucleus

_{50}^{120} S n

into its constituent nucleons is :
(Mass of

_{50}^{120} S n =

119.902199 a m u

; mass
of proton

= 1.007825 a m u

and mass of neutron

= 1.008665 a m u

)

Toppr Admin · Accepted Answer

Z-50-A-x2212-Z-120-x2212-50-70

The energy required to separate the typical middle mass nucleus $_{50}^{120} S n$ into its constituent nucleons is :
(Mass of $_{50}^{120} S n =$ $119.902199 a m u$ ; mass
of proton $= 1.007825 a m u$ and mass of neutron $= 1.008665 a m u$ )
$921 M e V$
$821 M e V$
$1021 M e V$
$1121 M e V$