The energy stored in a sphere of 10 cm radius when the sphere is charged to a potential difference of 300 V is4times 10-7-J5times 10-7-J3times 10-6-J2times 10-6-J

Question

Toppr Admin · Accepted Answer

The capacitance of spherical capacitor is given as: $C = \frac{4 π ϵ_{\circ} R r}{R - r}$
The constant $K = \frac{1}{4 π ϵ_{0}} = 9 \times 10^{9}$ Farad/m
If $R \to \infty$ $C = 4 π ϵ_{\circ} r$
For $r = 10$ cm; $C = \frac{0.1}{9 \times 10^{- 9}}$
The energy stored in a capacitor is given as: $E = \frac{1}{2} C V^{2}$
$E = \frac{1}{2} C v^{2} = \frac{1}{2} \times \frac{10^{- 10}}{9} \times 300^{2} J$

$E = 5 \times 10^{- 7} J$

The energy stored in a sphere of 10 cm radius when the sphere is charged to a potential difference of 300 V is4×10−7J5×10−7J3×10−6J2×10−6J

The capacitance of spherical capacitor is given as: C=4πϵ∘RrR−rThe constant K=14πϵ0=9×109 Farad/mIf R→∞ C=4πϵ∘rFor r=10 cm; C=0.19×10−9The energy stored in a capacitor is given as: E=12CV2E=12Cv2=12×10−109×3002JE=5×10−7J

The energy stored in a sphere of $10$ cm radius when the sphere is charged to a potential difference of $300$ V is

$4 \times 10^{- 7} J$
$5 \times 10^{- 7} J$
$3 \times 10^{- 6} J$
$2 \times 10^{- 6} J$