The correct option is C1 root Given equation: (x+2)(x−5)(x−3)(x+6)=x−2x+4
⇒(x+2)(x−5)(x+4)−(x−2)(x−3)(x+6)
Was this answer helpful?
4
Similar Questions
Q1
Assertion :The number of minimum possible complex roots of the equation x6−3x5+4x3+3x2+4=0 is 2 Reason: The equation x6−3x5+4x3+3x2+4=0 has maximum four real roots.
View Solution
Q2
The number of roots of the equation (x+2)(x−5)(x−3)(x+6)=x−2x+4 is
View Solution
Q3
Solve the following equation that has equal roots: x6−2x5−4x4+12x3−3x2−18x+18=0.
View Solution
Q4
Solve the following quadratic equation by factorization, the sum of the roots are : 1(x−1)(x−2)+1(x−2)(x−3)+1(x−3)(x−4)=16
View Solution
Q5
Determine the sum of imaginary roots of the equation (2x2+x−1)(4x2+2x−3)=6