0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The equation of motion of a particle executing SHM is (d2xdt2)+kx=0. The time period of the particle will be ?
  1. 2πk
  2. 2π
  3. 2πk
  4. 2πk

A
2π
B
2πk
C
2πk
D
2πk
Solution
Verified by Toppr

The equation of motion,

d2xdt2+kx=0

a=kx

ω2=k (a=ω2x)

ω=k

2πT=k

Time period,

T=2πk

The correct option is A.

Was this answer helpful?
36
Similar Questions
Q1
The equation of motion of a particle executing SHM is (d2xdt2)+kx=0. The time period of the particle will be ?
View Solution
Q2

The equation of motion of a particle is d2ydt2+Ky=0 , where K is positive

constant. The time period of the motion is given by


View Solution
Q3
The acceleration d2xdt2 of a particle varies with displacement x as d2xdt2=kx, where k is a constant of the motion.The time period T of the motion is equal to
View Solution
Q4
The time period of the simple harmonic motion represented by the equation d2xdt2+αx=0 is
View Solution
Q5
If an SHM is represented by d2xdt2+αx=0, then time period of the SHM is
View Solution