The equation of motion of a particle executing SHM is (d2xdt2)+kx=0. The time period of the particle will be ?

2π√k

2π

2πk

2π√k

A

2π

B

2πk

C

2π√k

D

2π√k

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Solution

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The equation of motion,

d2xdt2+kx=0

a=−kx

ω2=k (a=−ω2x)

ω=√k

2πT=√k

Time period,

T=2π√k

The correct option is A.

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