The equation of motion of a particle executing SHM is $(\frac{d^{2} x}{d t^{2}}) + k x = 0$ . The time period of the particle will be ?

Question

The equation of motion of a particle executing SHM is -dfrac-d-2x-dt-2-kx-0- The time period of the particle will be -dfrac-2pi -sqrt-k- 2pi2pi k2pi sqrt-k-

Toppr Admin · Accepted Answer

The equation of motion-d2xdt2-kx-0a-x2212-kx-x3C9-2-k-xA0- -xA0- -a-x2212-x3C9-2x-x3C9-x221A-k2-x3C0-T-x221A-kTime period-T-2-x3C0-x221A-kThe correct option is A-

The equation of motion of a particle executing SHM is $(\frac{d^{2} x}{d t^{2}}) + k x = 0$ . The time period of the particle will be ?
$\frac{2 π}{\sqrt{k}}$
$2 π$
$2 π k$
$2 π \sqrt{k}$

The equation of motion,

$\frac{d^{2} x}{d t^{2}} + k x = 0$

$a = - k x$

$ω^{2} = k$ ( $a = - ω^{2} x$ )

$ω = \sqrt{k}$

$\frac{2 π}{T} = \sqrt{k}$

Time period,

$T = \frac{2 π}{\sqrt{k}}$

The correct option is A.

The equation of motion of a particle executing SHM is (d2xdt2)+kx=0. The time period of the particle will be ?2π√k2π2πk2π√k

The equation of motion,d2xdt2+kx=0a=−kxω2=k (a=−ω2x)ω=√k2πT=√kTime period,T=2π√kThe correct option is A.

The equation of motion of a particle executing SHM is $(\frac{d^{2} x}{d t^{2}}) + k x = 0$ . The time period of the particle will be ?
$\frac{2 π}{\sqrt{k}}$
$2 π$
$2 π k$
$2 π \sqrt{k}$

The equation of motion,

$\frac{d^{2} x}{d t^{2}} + k x = 0$

$a = - k x$

$ω^{2} = k$ ( $a = - ω^{2} x$ )

$ω = \sqrt{k}$

$\frac{2 π}{T} = \sqrt{k}$

Time period,

$T = \frac{2 π}{\sqrt{k}}$

The correct option is A.