The equation of motion of a particle started at t=0 is given by x=5sin(20t+3π), where x is in cm and t in sec. When does the particle first have maximum speed?
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Updated on : 2022-09-05
Solution
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X=5sin(20t+3π) v=dtdx=100cos(20t+3π) a=dtdv=−2000sin(20t+3π) v=0 for the first time when, 20t+3π=2π ∴t=120π s