The equation of simple harmonic wave is given by $y = 5$ sin $\frac{5}{2} (100 t - x)$ , where $x$ and $y$ are in meter and time is in second. The time period of the wave (in second) will be.

Question

The equation of simple harmonic wave is given by y-5sin dfrac-5-2-100 t - x- where x and y are in meter and time is in second- The time period of the wave -in second- will be-0-040-060-010-05

Toppr Admin · Accepted Answer

The correct option is B 0-06y-5sin -x3C0-2-100t-x2212-x-y-Asin-x3C9-t-x2212-kx-x3C9-2-x3C0-TT-2-x3C0-100-x21D2-T-0-06Hence- the correct option is -B-

The equation of simple harmonic wave is given by $y = 5$ sin $\frac{5}{2} (100 t - x)$ , where $x$ and $y$ are in meter and time is in second. The time period of the wave (in second) will be.
$0.04$
$0.06$
$0.01$
$0.05$

The correct option is B $0.06$
$y = 5$ sin $\frac{π}{2} (100 t - x)$
$y = A$ sin $(ω t - k x)$
$ω = \frac{2 π}{T}$
$T = \frac{2 π}{100}$
$\Rightarrow T = 0.06$
Hence, the correct option is $(B)$

The equation of simple harmonic wave is given by y=5sin 52(100t−x), where x and y are in meter and time is in second. The time period of the wave (in second) will be.0.040.060.010.05

The correct option is B 0.06y=5sin π2(100t−x)y=Asin(ωt−kx)ω=2πTT=2π100⇒T=0.06Hence, the correct option is (B)

The equation of simple harmonic wave is given by $y = 5$ sin $\frac{5}{2} (100 t - x)$ , where $x$ and $y$ are in meter and time is in second. The time period of the wave (in second) will be.
$0.04$
$0.06$
$0.01$
$0.05$

The correct option is B $0.06$
$y = 5$ sin $\frac{π}{2} (100 t - x)$
$y = A$ sin $(ω t - k x)$
$ω = \frac{2 π}{T}$
$T = \frac{2 π}{100}$
$\Rightarrow T = 0.06$
Hence, the correct option is $(B)$