Question

$y_{1}$ = a sin $(ωt+ϕ)$ & $y_{2}$ = a cos $(ωt)$.

The phase difference of the velocities of the two particles is :

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Updated on : 2022-09-05

Solution

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Correct option is D)

$y_{2}=acos(ωt)$

$y_{1}=aωcos(ωt+ϕ)=aωsin(ωt+ϕ+π/_{2})$

$y_{2}=−aωsin(ωt)=aωsin(π+ωt)$

therefore phase difference$=ωt+ϕ+π/_{2}−(π+ωt)$

$=ϕ−π/_{2}$

Solve any question of Oscillations with:-

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