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y1 = a sin (ωt+ϕ) & y2 = a cos (ωt).

The phase difference of the velocities of the two particles is :

- π2+ϕ
- −ϕ
- ϕ−π2
- ϕ

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Solution

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y2=acos(ωt)

y1=aωcos(ωt+ϕ)=aωsin(ωt+ϕ+π/2)

y2=−aωsin(ωt)=aωsin(π+ωt)

therefore phase difference=ωt+ϕ+π/2−(π+ωt)

=ϕ−π/2

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