The equation of the line passing through the points (2,3) and (4,5) is
x−y−1=0
x+y−1=0
x−y+1=0
x+y+1=0
A
x+y−1=0
B
x−y−1=0
C
x−y+1=0
D
x+y+1=0
Open in App
Solution
Verified by Toppr
The equation of a line passing through two points (x1,y1)&(x2,y2) is given by y−y1x−x1=y2−y1x2−x1. ∴ The equation of line passing through (2,3) and (4,5) is given by y−3x−2=5−34−2
⟹y−3x−2=22 ⟹y−3=x−2 ⟹x−y+1=0
Hence, option D is correct.
Was this answer helpful?
33
Similar Questions
Q1
Find the equation of the line passing through the points (2, 3) and the point of intersection of the lines 4x−3y=7 and 3x+4y+1=0.
View Solution
Q2
Equation of the line passing through (1, 2) and parallel to the line y=3x–1 is .
View Solution
Q3
The equation of a line passing through (−2,3) and parallel to the tangent at origin for circle x2+y2+x−y=0 is:
View Solution
Q4
The equation of a line passing through the intersection of lines x = 0 and y = 0 and through the point (2, 2) is ________.
View Solution
Q5
The equation of a line passing through the intersection of lines x = 0 and y = 0 and through the point (2, 2), is .