The equilibrium constant can be related with energy change as $\frac{d}{d T} ln K_{c} = Δ H / R T^{2}$ .
If true enter 1, if false enter 0.

Question

The equilibrium constant can be related with energy change as displaystylefrac - d - dT - ln - - K - c - - - Delta H - R- T - 2 - -If true enter 1- false enter 0-

Toppr Admin · Accepted Answer

The equilibrium constant can be related with energy change as $\frac{d}{d t} ln K_{c} = Δ H / R T^{2}$ .
This is the differential form of Vant Hoff equation.
It relates the equilibrium constant with enthalpy change for the reaction.
The integrated form is as shown below.
$l o g \frac{K_{2}}{K_{1}} = \frac{Δ H^{0}}{2.303 R} \frac{T_{2} - T_{1}}{T_{1} T_{2}}$
It relates the equilibrium constants at two different temperatures with standard enthalpy change of the reaction.

The equilibrium constant can be related with energy change as ddTlnKc=ΔH/RT2.If true enter 1, if false enter 0.

The equilibrium constant can be related with energy change as $\frac{d}{d T} ln K_{c} = Δ H / R T^{2}$ .
If true enter 1, if false enter 0.