The equilibrium constant can be related with energy change as $\frac{d}{d T} ln K_{c} = Δ H / R T^{2}$ .
If true enter 1, if false enter 0.

Question

Answer 1

The equilibrium constant can be related with energy change as $\frac{d}{d t} ln K_{c} = Δ H / R T^{2}$ .
This is the differential form of Vant Hoff equation.
It relates the equilibrium constant with enthalpy change for the reaction.

The integrated form is as shown below.

$l o g \frac{K _{2}}{K _{1}} = \frac{Δ H ^{0}}{2 . 3 0 3 R} \frac{T _{2} - T _{1}}{T _{1} T _{2}}$

It relates the equilibrium constants at two different temperatures with standard enthalpy change of the reaction.

Answer 2

The equilibrium constant can be related with energy change as

\frac{d}{d t} ln K_{c} = Δ H / R T^{2}

.
This is the differential form of Vant Hoff equation.
It relates the equilibrium constant with enthalpy change for the reaction.

The integrated form is as shown below.

l o g \frac{K _{2}}{K _{1}} = \frac{Δ H ^{0}}{2 . 3 0 3 R} \frac{T _{2} - T _{1}}{T _{1} T _{2}}

It relates the equilibrium constants at two different temperatures with standard enthalpy change of the reaction.