The equilibrium constant a reaction is 10- what will be value of displaystyle bigtriangleup G-ominus - - R -8-314 displaystyle JK-1- mol-1- - T-300 K

Question

The equilibrium constant a reaction is 10- what will be value of  displaystyle bigtriangleup G-ominus -  - R -8-314  displaystyle JK-1- mol-1- - T-300 K

Toppr Admin · Accepted Answer

-x394-G0-x2212-2-303RTlogK-x2212-2-303-xD7-8-314-xD7-300log10-x2212-5-744kJ-mol

The equilibrium constant for a reaction is 10. what will be value of $△ G^{⊖}$ ? R =8.314 $J K^{- 1} m o l^{- 1}$ , T=300 K

$Δ G^{0} = - 2.303 R T l o g K = - 2.303 \times 8.314 \times 300 l o g 10 = - 5.744 k J / m o l$

The equilibrium constant for a reaction is 10. what will be value of △G⊖ ? R =8.314 JK−1mol−1, T=300 K

ΔG0=−2.303RTlogK=−2.303×8.314×300log10=−5.744kJ/mol

The equilibrium constant for a reaction is 10. what will be value of $△ G^{⊖}$ ? R =8.314 $J K^{- 1} m o l^{- 1}$ , T=300 K

$Δ G^{0} = - 2.303 R T l o g K = - 2.303 \times 8.314 \times 300 l o g 10 = - 5.744 k J / m o l$