Question

The equilibrium constant of the reaction;
$Cu\left(s\right)+2{Ag}^{+}\left(aq\right)⟶{Cu}^{2+}\left(aq\right)+2Ag\left(s\right)$
$E^o=0.46V$ at $298K$

• A. $2.0\times {10}^{10}$
• B. $2.4\times {10}^{10}$
• C. $4.0\times {10}^{10}$
• D. $4.0\times {10}^{15}$

Answer 1

Answer: (D)

The correct option is D $4.0\times {10}^{15}$
$Cu\left(s\right)+2{Ag}^{2+}\left(aq\right)⟶{Cu}^{2+}\left(aq\right)+2Ag\left(s\right)$
$E^o=0.46V$ at $298K$
$\log K_C=\frac{nF{E}^o}{RT}$
$=\frac{2\times 0.46}{0.059}$
$K_C=4\times {10}^{15}$