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Parallel and Series Combination of Capacitors

Question

The equivalent capacitance between $A$ and $B$ in the circuit given below is:

$2.4 μ F$
$4.9 μ F$
$3.6 μ F$
$5.4 μ F$

A

2.4 μ F

B

3.6 μ F

C

5.4 μ F

D

4.9 μ F

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Solution

Verified by Toppr

$C_{1} = 5 + 5 + 2 = 12 μ F$
$C_{2} = 4 + 2 = 6 μ F$
$1 / C_{E q} = 1 / 6 + 1 / 12 + 1 / 6 = 5 / 12$
$C_{E q} = 2.4 μ F$

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