Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Combination of Capacitors

Question

In Fig., each capacitance $$C_1$$ is $$6.0\mu F$$, and each capacitance $$C_2$$ is $$4.0\mu F$$.
The equivalent capacitance of the network between points a and b is?

A

$$2\mu F$$

B

$$4\mu F$$

C

$$8\mu F$$

D

$$6\mu F$$

Open in App

Solution

Verified by Toppr

Correct option is A. $$2\mu F$$

Was this answer helpful?

0

Similar Questions

Q1

In Fig., each capacitance $$C_1$$ is $$6.0\mu F$$, and each capacitance $$C_2$$ is $$4.0\mu F$$.
The equivalent capacitance of the network between points a and b is?

View Solution

Q2

In Fig., each capacitance $$C_1$$ is $$6.0\mu F$$, and each capacitance $$C_2$$ is $$4.0\mu F$$.
With $$420$$V across a and b, the value of $$(V_c-V_d)$$ is?

View Solution

Q3

Take

C_{1} = 4.0 μ F

and

C_{2} = 6.0 μ F

in the figure. Calculate the equivalent capacitance of the combination between the points indicated.

View Solution

Q4

In the figure shown, each capacitance

C_{1}

is

6.0 μ F

and each capacitance

C_{2}

is

4.0 μ F

. With

420 V

across

a

and

b

, the value of

V_{c} - V_{d}

is :

View Solution

Q5

In the figure shown, each capacitance

C_{1}

is

6.0 μ F

and each capacitance

C_{2}

is

4.0 μ F

. The charge on

C_{1}

nearest to

a

when

V_{a b} = 420 V

is :

View Solution