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Standard XII
Mathematics
Question
The expansion of
(
x
+
1
)
(
x
−
2
)
(
x
+
3
)
is
x
3
+
2
x
2
−
5
x
−
6
x
3
−
2
x
2
+
5
x
−
6
x
3
+
2
x
2
+
5
x
−
6
x
3
+
2
x
2
+
5
x
+
6
A
x
3
+
2
x
2
−
5
x
−
6
B
x
3
−
2
x
2
+
5
x
−
6
C
x
3
+
2
x
2
+
5
x
−
6
D
x
3
+
2
x
2
+
5
x
+
6
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Solution
Verified by Toppr
(
x
+
1
)
(
x
−
2
)
(
x
+
3
)
(
x
2
−
2
x
+
x
−
2
)
(
x
+
3
)
(
x
2
−
x
−
2
)
(
x
+
3
)
x
3
+
3
x
2
−
x
2
−
3
x
−
2
x
−
6
=
x
3
+
2
x
2
−
5
x
−
6
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Similar Questions
Q1
Factorise:
x
3
−
2
x
2
−
5
x
+
6
View Solution
Q2
Solve :
f
(
x
)
=
(
x
3
−
2
x
2
−
5
x
+
6
)
<
0
View Solution
Q3
Factorise the following polynomial.
x
3
−
2
x
2
−
5
x
+
6
View Solution
Q4
Find the degree of the following polynomial.
x
3
+
2
x
2
−
5
x
−
6
View Solution
Q5
I
f
a
,
β
,
1
are the roots of
x
3
−
2
x
2
−
5
x
+
6
=
0
then 3
a
+
β
=
_
_
_
_
_
_
_
i
f
a
>
0
View Solution