The external diameter of a 314m long copper tube is 1.2cm and the internal diameter is 1cm. Calculate its resistance if the specific resistance of copper is 2.2×10−8Ω−m?
0.2Ω
5.0×10−2Ω
3.14×10−2Ω
2.2×10−2Ω
4.4×10−2Ω
A
5.0×10−2Ω
B
4.4×10−2Ω
C
0.2Ω
D
3.14×10−2Ω
E
2.2×10−2Ω
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Solution
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The correct option is E0.2Ω Given, lengthl=314m Specific resistance ρl=2.2×10−8Ω−m External diameter D1=1.2×10−2m Internal diameter D2=1×10−2m As resistance of tube R=ρlA or R=ρlπ[D21−D22][∵A=πr2] or R=4×2.2×10−8×314π[(1.2)2−(1.0)2]×10−4 =0.2Ω.
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