The figure shows electric field lines penetrating two surfaces. Then

$| E_{a} | = | E_{a} |$
$| E_{a} | > | E_{a} |$
$| E_{a} | < | E_{a} |$
None of these

Question

The figure shows electric field lines penetrating two surfaces- Then-E-a- - -E-a-E-a- - -E-a-E-a- - -E-a-None of these

Toppr Admin · Accepted Answer

From figure we can see that number of electric field passing through per unit area is more for plate A than plate B-Hence- magnitude of field at A is greater than B-EA-gt-EB-

The figure shows electric field lines penetrating two surfaces. Then|Ea|=|Ea||Ea|>|Ea||Ea|<|Ea|None of these

From figure we can see that number of electric field passing through per unit area is more for plate A than plate B.Hence, magnitude of field at A is greater than B.|EA|>|EB|

The figure shows electric field lines penetrating two surfaces. Then

$| E_{a} | = | E_{a} |$
$| E_{a} | > | E_{a} |$
$| E_{a} | < | E_{a} |$
None of these

From figure we can see that number of electric field passing through per unit area is more for plate A than plate B.

Hence, magnitude of field at A is greater than B.

$| E_{A} | > | E_{B} |$