#### The graph could be representing a ball rebounding between two walls separated by 2 cm with a constant velocity in free space. After receiving the impulse ball changes its direction. Hence time between two impulses is 2 seconds.

$$velocity = \frac{displacement}{time} = \frac{2 \times 10^{-2}}{2} = 0.01 \ m/s$$

Initial momentum,

$$mu = 0.04 \times 10^{-2} \ kgm/s$$

Final momentum,

$$mv = - 0.04 \times 10^{-2} kgm/s$$

$$\therefore$$ Change in momentum = 0.08 \times 10^{-2} kgm/s $$