0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The figure shows two identical parallel plate capacitors connected to a battery with the switch S closed. The switch is now opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant (or relative permittivity) 3.Find the ratio of the total electrostatic energy stored in both capacitors before and after the introduction of the dielectric.
1011216_1e636ca1609b401491e07e6d5a493fa4.png
  1. 23
  2. 53
  3. 35
  4. 32

A
32
B
23
C
53
D
35
Solution
Verified by Toppr

Energy in each capacitor is 12cV2
when switch is opened
Q on 2nd capacitor is cv even after introduction of dielectric Q remain same but C will become KC
Energy =Q22C2=(cv)22(K1)=cv22k
Energy is set is 12cv2
same as before
after dielectric insertion
c become kc
Energy =12(kc)v2
=kcv22
Total energy initially =12cv2+12cv2=cv2------(1)
Total energy after opening switch =kcv22+cv22k
=cv22(k+1k)
put k=3
=cv2(10)2×3=5cv23-----(2)
(1) ÷ (2)
=3/5

1432645_1011216_ans_cbf176e3b39f42c499be09d98d514914.png

Was this answer helpful?
4
Similar Questions
Q1
The figure shows two identical parallel plate capacitors connected to a battery with the switch S closed. The switch is now opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant (or relative permittivity) 3.Find the ratio of the total electrostatic energy stored in both capacitors before and after the introduction of the dielectric.
1011216_1e636ca1609b401491e07e6d5a493fa4.png
View Solution
Q2
The figure shows two identical parallel plate capacitors connected to a battery with switch S closed. The switch is now opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant (or relative permittivity) 3. The ratio of the total electrostatic energy stored in both capacitors before and after the introduction of the dielectric is x5. Then find the value of x
View Solution
Q3
Figure given shows two identical parallel plate capacitors connected to a battery with switch S closed. The switch is now opened and the free space between the plate of capacitors is filled with a dielectric of dielectric constant 2. What will be the ratio of total electrostatic energy stored in both capacitors before and after the introduction of the dielectric?
678419_d143353f908340afa0e6934cf71ecb66.png
View Solution
Q4
Two identical parallel plate capacitors A and B(parallel)are connected to a batteryof
V volts with the switch S closed. The switch is now opened and the free
space between the plates of the capacitors is filled with a dielectric of
dielectric constant K. Find the ratio of the total electrostatic energy stored
in both capacitors before and after the introduction of the
dielectric.
View Solution
Q5
Figure shows two identical parallel plate capacitors connected to a battery through a switch S. Initially, the switch is closed so that the capacitors are completely charged. The switch is now opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant 3. Find the ratio of the initial total energy stored in the capacitors to the final total energy stored.

View Solution