The focal length of a lens of refractive index $μ$ is $f$ . If the lens is immersed in a liquid of refractive index $μ$ then the focal length of lens is

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Answer 1

$\frac{1}{f} = (n - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}})$
where, $n$ is refractive index of lens material with respect to its surrounding medium
If lens is immersed in the liquid of refractive index equal to its own then $n = 1$ and hence above equation becomes: $\frac{1}{f} = 0$

$\Rightarrow f = \infty$

Answer 2

\frac{1}{f} = (n - 1) (\frac{1}{R _{1}} - \frac{1}{R _{2}})

where,

n

is refractive index of lens material with respect to its surrounding medium

If lens is immersed in the liquid of refractive index equal to its own then

n = 1

and hence above equation becomes:

\frac{1}{f} = 0

\Rightarrow f = \infty

The focal length of a lens of refractive index $μ$ is $f$ . If the lens is immersed in a liquid of refractive index $μ$ then the focal length of lens is

$\frac{f}{2}$

$2 f$

$infinite$

$zero$

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The focal length of a lens of refractive index μ is f. If the lens is immersed in a liquid of refractive index μ then the focal length of lens is

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f1​=(n−1)(R1​1​−R2​1​) where, n is refractive index of lens material with respect to its surrounding mediumIf lens is immersed in the liquid of refractive index equal to its own then n=1 and hence above equation becomes: f1​=0 ⇒f=∞

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