The focal length of objective lens and eyepiece a compound microscope are 0-95 and 5 cm and they are placed 20 cm from each other final image is formed 25 cm in eyepiece the magnifying power of the microscope-

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L-20cmfo-0-95cmfe-5cmD-25cm-x3BC-p-LDfofe-20-x2217-250-95-x2217-5-105-26

The focal length of objective lens and eyepiece for a compound microscope are $0.95$ and $5$ cm and they are placed at $20$ cm from each other final image is formed at $25$ cm in eyepiece find the magnifying power of the microscope?

$L = 20 c m$
$f_{o} = 0.95 c m$
$f_{e} = 5 c m$
$D = 25 c m$
$μ_{p} = \frac{L D}{f_{o} f_{e}} = \frac{20 * 25}{0.95 * 5} = 105.26$

The focal length of objective lens and eyepiece for a compound microscope are 0.95 and 5 cm and they are placed at 20 cm from each other final image is formed at 25 cm in eyepiece find the magnifying power of the microscope?

L=20cmfo=0.95cmfe=5cmD=25cmμp=LDfofe=20∗250.95∗5=105.26

The focal length of objective lens and eyepiece for a compound microscope are $0.95$ and $5$ cm and they are placed at $20$ cm from each other final image is formed at $25$ cm in eyepiece find the magnifying power of the microscope?

$L = 20 c m$
$f_{o} = 0.95 c m$
$f_{e} = 5 c m$
$D = 25 c m$
$μ_{p} = \frac{L D}{f_{o} f_{e}} = \frac{20 * 25}{0.95 * 5} = 105.26$