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>> $The focal length of objective lens and e$

Question

The focal length of objective lens and eyepiece for a compound microscope are $0.95$ and $5$ cm and they are placed at $20$ cm from each other final image is formed at $25$ cm in eyepiece find the magnifying power of the microscope?

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Updated on : 2022-09-05

Solution

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$L = 20 c m$
$f_{o} = 0.95 c m$
$f_{e} = 5 c m$
$D = 25 c m$
$μ_{p} = \frac{L D}{f _{o} f _{e}} = \frac{2 0 * 2 5}{0 . 9 5 * 5} = 105.26$

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