Here, fv=2 cm and fe=3 cm.
Using lens formula for eyepiece, −1u+1v1=1fe
⇒−1u+1∝=13⇒u1=−3 cm[∵i=0]
But the distance between objective and eyepiece is 15 cm (given).
Therefore, distance of image formed by the objective, v=15−3=12 cm. Let u be the object distance from the objective, then for objective lens −1u+1v=1f0 or −1u+112=12
⇒−1u=12−112=512u=−125=2.4 cm
a. is the correct option.