The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f.
Daily pocket allowance (in Rs.)
11−13
13−15
15−17
17−19
19−21
21−23
23−25
Number of children
7
6
9
13
f
5
4
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Solution
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Lets take assumed mean, A as 16
Class interval =2
∴ui=xi−Ah=xi−162
Now, we have A=16,¯x=18 and h=2
We know that,
Mean, ¯x=A+h(1N∑fiui)
⇒18=16+2(2f+24f+44)
⇒2f+24f+44=1
⇒f+44=2f+24
⇒f=20
Hence, the value of missing frequency, f=20
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Similar Questions
Q1
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f.
Daily pocket allowance (in Rs.)
11−13
13−15
15−17
17−19
19−21
21−23
23−25
Number of children
7
6
9
13
f
5
4
View Solution
Q2
The following distribution shows the daily pocket allowance of children of a locality. If the mean pocket allowance is Rs. 18, find the missing frequency f. Daily pocketallowance(in Rs)11−1313−1515−1717−1919−2121−2323−25Frequency76913f54
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Q3
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f.