The following is NOT equal to $0$ in the Boolean algebra is

(A) For $A=0$,
$\overline{\bar{A}.A}=\overline{\bar{0}.0}=\overline{1.0}=\bar{0}=1$  
For $A=1$,
$\overline{\bar{A}.A}=\overline{\bar{1}.1}=\overline{0.1}=\bar{0}=1$  

(B) For $A=0$,
$A.\bar{A}=0.\bar{0}=0.1=0$
For $A=1$,
$A.\bar{A}=1.\bar{1}=1.0=0$

(C) For $A=0$,
$A.0=0.0=0$
For $A=1$,
$A.0=1.0=0$

(D) For $A=0$,
$\overline{A+\bar{A}}=\overline{0+\bar{0}}=\overline{0+1}=\bar{1}=0$
For $A=1$,
$\overline{A+\bar{A}}=\overline{1+\bar{1}}=\overline{1+0}=\bar{1}=0$