The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :

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Answer 1

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.

Answer 2

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.

The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :

$\frac{q}{V \times B}$

$\frac{V \times B}{q}$

$q (V \times B)$

$(V . B) q$

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.

A charged particle is moving with velocity $v$ in a magnetic field of induction $B$ . The force on the particle will be maximum when

A charge q is moving with a velocity v parallel to a magnetic field B. Force on the charge due to magnetic field is

A charge moving with velocity v in X - direction is subjected to a field of magnetic induction in the negative X direction. As a result the charge will

A charge moving with velocity $v$ in $X -$ direction is subjected to a field of magnetic induction in the negative $X$ direction. As a result the charge will :

An alpha particle in an electric field of intensity $E$ experiences the same force as when it moves perpendicular to a magnetic field of induction $B$ . The magnitude of its velocity in the magnetic field is given by

Revise with Concepts

Magnetic Field and Magnetic Force

The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :

V×Bq​

qV×B​

q(V×B)

(V.B)q

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.

A charged particle is moving with velocity v in a magnetic field of induction B. The force on the particle will be maximum when

A charge q is moving with a velocity v parallel to a magnetic field B. Force on the charge due to magnetic field is

A charge moving with velocity v in X - direction is subjected to a field of magnetic induction in the negative X direction. As a result the charge will

A charge moving with velocity v in X− direction is subjected to a field of magnetic induction in the negative X direction. As a result the charge will :

An alpha particle in an electric field of intensity E experiences the same force as when it moves perpendicular to a magnetic field of induction B. The magnitude of its velocity in the magnetic field is given by

Revise with Concepts

Magnetic Field and Magnetic Force

$\frac{q}{V \times B}$

$\frac{V \times B}{q}$

$q (V \times B)$

$(V . B) q$

A charged particle is moving with velocity $v$ in a magnetic field of induction $B$ . The force on the particle will be maximum when

A charge moving with velocity $v$ in $X -$ direction is subjected to a field of magnetic induction in the negative $X$ direction. As a result the charge will :

An alpha particle in an electric field of intensity $E$ experiences the same force as when it moves perpendicular to a magnetic field of induction $B$ . The magnitude of its velocity in the magnetic field is given by