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Question

# The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :q(→V×→B)(→V.→B)q→V×→Bqq→V×→B

A
V×Bq
B
(V.B)q
C
qV×B
D
q(V×B)
Solution
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#### The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.

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