The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :
$q (\to V \times \to B)$
$(\to V . \to B) q$
$\frac{\to V \times \to B}{q}$
$\frac{q}{\to V \times \to B}$

Question

The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by -q-vec-V-times vec-B-vec-V-vec-B-qdfrac-vec-V-times vec-B-q-dfrac-q-vec-V-times vec-B-

Toppr Admin · Accepted Answer

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule - The force is given by the charge times the vector product of velocity and magnetic field-

The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :q(→V×→B)(→V.→B)q→V×→Bqq→V×→B

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.

The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :
$q (\to V \times \to B)$
$(\to V . \to B) q$
$\frac{\to V \times \to B}{q}$
$\frac{q}{\to V \times \to B}$