The force acting on a charge q moving with a velocity V in a magnetic field of induction B is given by :

A

$V×Bq $

B

$qV×B $

C

$q(V×B)$

D

$(V.B)q$

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Updated on : 2022-09-05

Solution

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Correct option is C)

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule . The force is given by the charge times the vector product of velocity and magnetic field.

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