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>>Magnetism and Matter
>>Properties of Magnetic Field
>> $The force between two similar poles of s$

Question

The force between two similar poles of strengths $10 A m$ and $40 A m$ separated by a distance of $20 c m$ is

A

$2 \times 1 0^{- 1} N$

B

$4 \times 1 0^{- 2} N$

C

$1 0^{- 3} N$

D

$4 \times 1 0^{- 3} N$

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Updated on : 2022-09-05

Solution

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Correct option is C)

$F = \frac{μ _{0}}{4 π} \frac{m _{1} m _{2}}{r ^{2}} = 1 0^{- 7} \times 10 \times 40 / (0.2)^{2} = 1 0^{- 3} N$

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