The force between two similar poles of strengths 10Am and 40Am separated by a distance of 20cm is
2×10−1N
4×10−2N
10−3N
4×10−3N
A
4×10−2N
B
4×10−3N
C
2×10−1N
D
10−3N
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Solution
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F=μ04πm1m2r2=10−7×10×40/(0.2)2=10−3N
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