The force of repulsion between two parallel wires is $f$ when each one of them carries a certain current $I$ . If the current in each is doubled, the force between them would be

Question

The force of repulsion between two parallel wires is F when each one of them carries a certain current I- If the current in each is doubled- the force between them would be8F4F2FF

Toppr Admin · Accepted Answer

The force per unit length on a current carrying wire due to another current carrying wire placed at a distance $d$ from it is

$\frac{F}{l} = \frac{μ_{0} I_{1} I_{2}}{2 π d}$

Hence when current in both wires is doubled, the force of repulsion becomes four times of that before.

The force of repulsion between two parallel wires is F when each one of them carries a certain current I. If the current in each is doubled, the force between them would be8F4F2FF

The force per unit length on a current carrying wire due to another current carrying wire placed at a distance d from it isFl=μ0I1I22πdHence when current in both wires is doubled, the force of repulsion becomes four times of that before.

The force of repulsion between two parallel wires is $F$ when each one of them carries a certain current I. If the current in each is doubled, the force between them would be
$8 F$
$4 F$
$2 F$
$F$

The force per unit length on a current carrying wire due to another current carrying wire placed at a distance $d$ from it is

$\frac{F}{l} = \frac{μ_{0} I_{1} I_{2}}{2 π d}$

Hence when current in both wires is doubled, the force of repulsion becomes four times of that before.