The formula of oxide of potassium with percentage of oxygen being $45.07 %$ is :
$K O_{2}$
$K_{2} O_{2}$
None of these
$K_{2} O$

Question

The formula of oxide of potassium with percentage of oxygen being 45-07- is -KO -2K-2O -2None of theseK-2O

Toppr Admin · Accepted Answer

The formula of an oxide of-xA0-potassium with the percentage of oxygen being 45-07- is KO2Here the percentage of oxygen is 3271-xD7-100-45-07 -32 is molecular weight of oxygen and 71 is the total molecular weight of KO2-So the compound is KO2

The formula of oxide of potassium with percentage of oxygen being 45.07% is :KO2K2O2None of theseK2O

The formula of an oxide of potassium with the percentage of oxygen being 45.07% is KO2Here the percentage of oxygen is 3271×100=45.07 (32 is molecular weight of oxygen and 71 is the total molecular weight of KO2)So the compound is KO2

The formula of oxide of potassium with percentage of oxygen being $45.07 %$ is :
$K O_{2}$
$K_{2} O_{2}$
None of these
$K_{2} O$

The formula of an oxide of potassium with the percentage of oxygen being $45.07 %$ is $K O_{2}$
Here the percentage of oxygen is $\frac{32}{71} \times 100 = 45.07$ (32 is molecular weight of oxygen and 71 is the total molecular weight of $K O_{2}$ )
So the compound is $K O_{2}$