The formula used surface area of cone is -s denotes slant height-displaystyle pi rleft- r-s right- sq-unitsdisplaystyle pi rleft- 2r-s right- sq-unitsdisplaystyle 2pi rleft- r-s right- sq-unitsdisplaystyle pi r- left- r-s right- - 2 - sq-units

Question

The formula used surface area of cone is -s denotes slant height-displaystyle pi rleft- r-s right-  sq-unitsdisplaystyle pi rleft- 2r-s right-  sq-unitsdisplaystyle 2pi rleft- r-s right-  sq-unitsdisplaystyle pi r- left- r-s right- - 2 - sq-units

Toppr Admin · Accepted Answer

Since- surface area of cone - -xA0-Area of sector - Area of circle-x3C0-rs-x3C0-r2-xA0-x3C0-r-r-s-Therefore- surface area of a cone - -x3C0-r-r-s- sq-units-Hence- option A is correct-

The formula used for surface area of cone is ( $s$ denotes slant height):
$π r (r + s)$ sq.units
$π r (2 r + s)$ sq.units
$2 π r (r + s)$ sq.units
$π r {(r + s)}^{2}$ sq.units

Since, surface area of cone $=$ Area of sector $+$ Area of circle
$= π r s + π r^{2}$ $= π r (r + s)$ .
Therefore, surface area of a cone $=$ $π r (r + s)$ sq.units.
Hence, option $A$ is correct.

The formula used for surface area of cone is (s denotes slant height):πr(r+s) sq.unitsπr(2r+s) sq.units2πr(r+s) sq.unitsπr(r+s)2 sq.units

Since, surface area of cone = Area of sector + Area of circle=πrs+πr2 =πr(r+s).Therefore, surface area of a cone = πr(r+s) sq.units.Hence, option A is correct.

The formula used for surface area of cone is ( $s$ denotes slant height):
$π r (r + s)$ sq.units
$π r (2 r + s)$ sq.units
$2 π r (r + s)$ sq.units
$π r {(r + s)}^{2}$ sq.units

Since, surface area of cone $=$ Area of sector $+$ Area of circle
$= π r s + π r^{2}$ $= π r (r + s)$ .
Therefore, surface area of a cone $=$ $π r (r + s)$ sq.units.
Hence, option $A$ is correct.