The four triangles formed by joining the midpoints of the sides of a triangle respectively are:
similar, not necessarily congruent
congruent
equilateral
isosceles
A
equilateral
B
congruent
C
isosceles
D
similar, not necessarily congruent
Open in App
Solution
Verified by Toppr
In △ABC
D is the midpoint of BC
E is the midpoint of BA
∴ by midpoint theorem, FO||AC
12AC=OF⇒OF=AE
Similarly OE=AB and EF=BC, using mid point theorem.
In △AFE;△DEF;△EDC
AF=DE=FB=ED, Proved
FE=EF=BO=DC, Proved
AE=OF=FO=EC Proved
By SSS congruency.
Was this answer helpful?
2
Similar Questions
Q1
The four triangles formed by joining the midpoints of the sides of a triangle respectively are:
View Solution
Q2
The four triangle formed by joining the midpoints of the sides of a triangle respectively are
View Solution
Q3
The four triangle formed by joining the mid-points of the sides of a triangle respectively are:
View Solution
Q4
Prove that the line segments joining the midpoints of the sides of a triangle from four triangles each of which is similar to the original triangle.
View Solution
Q5
The line segments joining the midpoints of the sides of a triangle form four triangles, each of which is
(a) congruent to the original triangle
(b) similar to the original triangle
(c) an isosceles triangle
(d) an equilateral triangle