The freezing point on a thermometer is marked as 20∘ and the boiling point as 150∘ . A temperature of 60∘C on this thermometer will be read as.
40∘
65∘
110∘
98∘
A
110∘
B
65∘
C
40∘
D
98∘
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Solution
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For any two thermometric scales, T1−LFP1UFP1−LFP1=T2−LFP2UFP2−LFP2
where LFPandUFP are Lower Fixed Point and Upper Fixed Point respectively.
∴Tcelsius−0100o=T−20o130o
⇒T=78o+20o=98o
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