The frequency of radiation emitted when the electron falls from n=4 to n=1 in a hydrogen atom will be (Given : ionisation energy of H=2.18×10−18Jatom−1 and h=6.626×10−34J−s)
1.54×1015s−1
1.03×1015s−1
3.08×1015s−1
2×1015s−1
A
1.54×1015s−1
B
1.03×1015s−1
C
3.08×1015s−1
D
2×1015s−1
Open in App
Solution
Verified by Toppr
The frequency of radiation emitted when the electron falls from n=4 to n=1 in a hydrogen atom will be 3.08×1015s−1
Was this answer helpful?
12
Similar Questions
Q1
The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be (given ionization energy of H=2.18×10−18atom−1 and h=6.606×10−34j−s)
View Solution
Q2
The frequency of radiations emitted when electron falls from n = 4, to n = 1, in H-atom would be:
(Given E1 for H=2.18×10-18 J atom -1 and h=6.625 ×10-34 Js.)
View Solution
Q3
The frequency of radiation emitted when the electron falls from n=4 to n=1 in a hydrogen atom will be (Given : ionisation energy of H=2.18×10−18Jatom−1 and h=6.626×10−34J−s)
View Solution
Q4
The frequency of radiation emitted when the electron falls from n=4 to n= lina hydrogen atom will be (Given ionisation energy of H=2.1810−18Jatom−1 and h=6.625×10−34Js)
View Solution
Q5
The maximum kinetic energy of the photoelectrons is found to be 6.63×10−19J. When the metal is irradiated with a radiation of frequency 2×1015Hz, the threshold frequency of the metal is about