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Standard XII
Maths
Question
The function
f
(
x
)
=
log
(
x
+
√
1
+
x
2
)
is an odd function.
true
false
A
True
B
False
Open in App
Solution
Verified by Toppr
Given the function is
f
(
x
)
=
log
(
x
+
√
1
+
x
2
)
.
Now
f
(
−
x
)
=
log
(
−
x
+
√
1
+
x
2
)
=
log
(
1
x
+
√
1
+
x
2
)
=
−
log
(
x
+
√
1
+
x
2
)
=
−
f
(
x
)
∀
x
.
So the function
f
(
x
)
is an odd function.
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