Solve
Guides
Join / Login
Use app
Login
0
You visited us
0
times! Enjoying our articles?
Unlock Full Access!
Standard XII
Maths
Question
The function
f
(
x
)
=
sin
(
log
(
x
+
√
1
+
x
2
)
)
is
odd funcition
even function
neither even nor odd
periodic function
A
periodic function
B
even function
C
odd funcition
D
neither even nor odd
Open in App
Solution
Verified by Toppr
f
(
x
)
=
sin
log
(
x
+
√
1
+
x
2
)
)
f
(
−
x
)
=
sin
log
(
−
x
+
√
1
+
x
2
)
)
f
(
−
x
)
=
sin
log
(
x
+
√
1
+
x
2
)
(
−
x
+
√
1
+
x
2
)
(
x
+
√
1
+
x
2
)
)
f
(
−
x
)
=
sin
log
1
(
x
+
√
1
+
x
2
)
)
f
(
−
x
)
=
sin
(
−
log
(
x
+
√
1
+
x
2
)
)
f
(
−
x
)
=
−
sin
(
log
(
x
+
√
1
+
x
2
)
)
−
f
(
x
)
=
f
(
−
x
)
Thus
f
(
x
)
is odd function
Was this answer helpful?
0
Similar Questions
Q1
The function
f
(
x
)
=
s
i
n
(
l
o
g
(
x
+
√
x
2
+
1
)
)
is
View Solution
Q2
The function
f
(
x
)
=
s
i
n
(
l
o
g
(
x
+
√
x
2
+
1
)
)
is
View Solution
Q3
The function
f
(
x
)
=
s
i
n
(
l
o
g
(
x
+
√
x
2
+
1
)
)
is
View Solution
Q4
The function
f
(
x
)
=
sin
(
log
(
x
+
√
x
2
+
1
)
)
View Solution
Q5
The function
f
(
x
)
=
l
o
g
(
x
+
√
x
2
+
1
)
, is
View Solution