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Standard XII
Chemistry
Dalton's Law of Partial Pressures
Question

The gaseous decomposition of Cl2O7 (gas) takes place according to following reaction:

Cl2O7→Cl2(g)+72O2(g)

The decomposition is carried out in a closed container. The pressure measured after 15 minute and after a very long time were found to be 375 mm of Hg and 900 mm of Hg respectively. The ratio of partial pressure of Cl2 gas after a very long time and after 15 minute is:


  1. 6
  2. 4
  3. 1
  4. 5

A
4
B
1
C
6
D
5
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Solution
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The gaseous decomposition takes place as

Cl2O7(g)→Cl2(g)+72O2(g)

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Similar Questions
Q1

The gaseous decomposition of Cl2O7 (gas) takes place according to following reaction:

Cl2O7→Cl2(g)+72O2(g)

The decomposition is carried out in a closed container. The pressure measured after 15 minute and after a very long time were found to be 375 mm of Hg and 900 mm of Hg respectively. The ratio of partial pressure of Cl2 gas after a very long time and after 15 minute is:


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Q2
The decomposition of a compound P, at temperature T according to the equation 2P(g)→4Q(g)+R(g)+S(l) is the first order reaction. After 30 minutes from the start of decomposition in a closed vessel, the total pressure developed is found to be 317 mm Hg and after a long period of time the total pressure observed to be 617 mm Hg.
The total pressure of the vessel after 75 minute, if the volume of liquid S is supposed to be negligible is:
(Given : Vapour pressure of S(l) at temperature T=32.5mm Hg)

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Q3
The decomposition of a compound P, at temperature T according to the equation
2P(g)→4Q(g)+R(g)+S(l) is the first order reaction. After 30 minutes from the start of decomposition in a closed vessel, the total pressure developed is found to be 317 mm Hg and after a long period of time the total pressure observed to be 617 mm Hg. Calculate the total pressure of the vessel after 75 minute, if volume of liquid S is supposed to be negligible. Also calculate the time fraction t7/8?
Given : Vapour pressure of S(l) at temperature T = 32.5 mm Hg.
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Q4
The decomposition of a compound A, at temperature T according to the equation
2P(g)→4Q(g)+R(g)+S(l)
is the first order reaction. After 30 minutes from the start of decomposition in a closed vessel, the total pressure developed is found to be 160.25 mm of Hg and after a long period of time the total pressure observed to be 220.25 mm of Hg. Calculate the total pressure of the vessel just after 2 hours in mm of Hg, if volume of liquid S is supposed to be
negligible.
Given : Vapour pressure of S (l) at temperature T = 20.25 mm of Hg.
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Q5
The decomposition of N2O5 according to equation: 2N2O5(g)→4NO2(g)+O2(g), is a first-order reaction. After 30 minutes from the start of the decomposition in a closed vessel, the total pressure developed is found to be 284.5 mm of Hg and on complete decomposition, the total pressure is 584.5 mm of Hg.
The rate constant of a reaction is:

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