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The gauge pressure in the main water pipe is 400 KPa. The work done to pump water at a gauge pressure of 100 KPa is $12 \times 10^{9} J$ . Then volume of water pumped is
$20 \times 10^{3} m^{3}$
$10 \times 10^{3} m^{3}$
$40 \times 10^{3} m^{3}$
$25 \times 10^{3} m^{3}$

A

20 \times 10^{3} m^{3}

B

25 \times 10^{3} m^{3}

C

10 \times 10^{3} m^{3}

D

40 \times 10^{3} m^{3}

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