Given, amount of water removed each time a pile is used = x
Initial amount of water in the tank = 5
Final amount of water in the tank = 212
From the given graph, we can observe that:
when the 6th pile is removed, volume of water left is 3 gallons and the number of piles used till that point is ′6′.
Hence, amount of water removed = (Number of piles used) × (Amount of water removed each time a pile is used)
(Initial Amount - of water in the tank) − (Amount of water left in the tank after 6 piles are removed) = 8 × x
⇒(5 − 3) = 6x
⇒2 = 6x
⇒x = 13
⇒x = 0.333
Therefore, the value of ′x′ is ′0.333′.