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Question

The graph between log Xm v/s log P is straight-line inclined at an angle 45o with intercept 0.30. What will be the rate of adsorption at pressure of 0.4 atm?
  1. 0.4
  2. 0.6
  3. 0.8
  4. 0.9

A
0.6
B
0.8
C
0.9
D
0.4
Solution
Verified by Toppr

Slope in equation is 1n = tan45o =1
Intercept is logk = 0.30, that implies k=2

Hence by equation xm=kp1/n

k=2, n=1 and p=0.4


Rate of adsorption, x/m is 0.8.

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