The greater reactivity of displaystyle - F - 2 - is due to -higher electronegativity of F-gaseous state of displaystyle - F - 2 -lower electron affinity of F-lower bond energy of displaystyle - F-F - bond-

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Toppr Admin · Accepted Answer

The greater reactivity of F2 is due to-xA0-lower bond energy of-xA0-F- F-xA0-bond and bond energy is lower because of charge repulsion between two F atoms -due to lower size of F atom charge density is high and repulsion is very high so bond energy is low-xA0-making its bond enthalpy lower-

The greater reactivity of $F_{2}$ is due to :
higher electronegativity of F.
gaseous state of $F_{2}$ .
lower electron affinity of F.
lower bond energy of $F - F$ bond.

The greater reactivity of $F_{2}$ is due to lower bond energy of F- F bond and bond energy is lower because of charge repulsion between two F atoms (due to lower size of F atom charge density is high and repulsion is very high so bond energy is low) making its bond enthalpy lower..

The greater reactivity of F2 is due to :higher electronegativity of F.gaseous state of F2.lower electron affinity of F.lower bond energy of F−F bond.

The greater reactivity of F2 is due to lower bond energy of F- F bond and bond energy is lower because of charge repulsion between two F atoms (due to lower size of F atom charge density is high and repulsion is very high so bond energy is low) making its bond enthalpy lower..

The greater reactivity of $F_{2}$ is due to :
higher electronegativity of F.
gaseous state of $F_{2}$ .
lower electron affinity of F.
lower bond energy of $F - F$ bond.

The greater reactivity of $F_{2}$ is due to lower bond energy of F- F bond and bond energy is lower because of charge repulsion between two F atoms (due to lower size of F atom charge density is high and repulsion is very high so bond energy is low) making its bond enthalpy lower..