The greatest number of points of intersection of 8 lines and 4 circles is:
104
64
92
96
A
64
B
92
C
96
D
104
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Solution
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Two lines will intersect at one point. So max numbers of point of intersection are given by 8C2
Two circles will intersect on two points at max, so total number of point of intersections of circles can be 4C2×2.
Now we can take a circle, a line and they will also intersect on 2 points
so total we have
8C2 + 4C2×2 + 2×4×8=104
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