Question

Between which two towns is the train journey fastest ?

Give a reason for your answer.

Verified by Toppr

1) Consider first part of the journey i.e. Audley to Brookland.

Distance between two stations is $10km$

Train left Audley at $9.00$ and reached Brookland at $9:20$

Thus, time taken by train to reach from Audley to Brookland is $20minutes$

Thus, average speed of the train between these two stations is given by,

$v_{1}=2010 minkm $

$∴v_{1}=21 minkm $ (1)

2) Consider second part of the journey i.e. Brookland to Cawley.

Distance covered by train between these two stations is $35−10=25km$

Train left Brookland at $9:25$ and reached Cawley at $9:40$

Thus, time taken by train to reach from Brookland to Cawley is $15minutes$

Thus, average speed of the train between these two stations is given by,

$v_{2}=1525 minkm $

$∴v_{2}=35 minkm $

Now, we have to compare two fractions i.e. $21 $ and $35 $

LCM of $2$ and $3$ is $6$

$21 =2×31×3 =63 $

$35 =3×25×2 =610 $

$610 >63 $

$∴35 >21 $

The train journey was fastest between Brookland and Cawley.

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