The train returns from Cawley to Audley at a speed of $$70\quad { km }/{ h }$$
Distance between these two stations is $$35\quad km$$
We know that $$speed=\frac { distance }{ time } $$
$$\therefore 70=\frac { 35 }{ t } $$
$$\therefore t=\frac { 35 }{ 70 } $$
$$\therefore t=\frac { 1 }{ 2 } \quad hour$$
$$\therefore t=\frac { 1 }{ 2 } \times 60\quad minutes$$
$$\therefore t=30\quad minutes$$