Question

The grid shows the travel graph for a train travelling from Audley to Cawley, stopping at Brookland.
Calculate the speed of the train, in kilometers per hour, between Brookland and Cawley.

Answer 1

Consider second part of the journey i.e. Brookland to Cawley.

Distance covered by train between these two stations is $$35-10=25\quad km$$

Train left Brookland at $$9:25$$ and reached Cawley at $$9:40$$

Thus, time taken by train to reach from Brookland to Cawley is $$15\quad minutes$$

Thus, average speed of the train between these two stations is given by,

$${ v }_{ 2 }=\frac { 25 }{ 15 } \quad \frac { km }{ min } $$

$$\therefore { v }_{ 2 }=\frac { 5 }{ 3 } \quad \frac { km }{ min } $$

$$\therefore { v }_{ 2 }=\frac { 5 }{ \left( \frac { 3 }{ 60 } \right) } \quad \frac { km }{ hour } $$

$$\therefore { v }_{ 2 }=\frac { 5\times 60 }{ 3 } \quad \frac { km }{ hour } $$

$$\therefore { v }_{ 2 }=100\quad \frac { km }{ hour } $$