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Question

The half cell involving the reaction Cr2O27(aq)+14H+(aq)+6e2Cr3+(aq)+7H2O can be represented as :
  1. Pt,H+(aq),Cr2O27(aq)
  2. Pt,H+,Cr3+(aq)
  3. Pt,H2,Cr2O27(aq),Cr3+(aq)
  4. Pt,H+,Cr2O27(aq),Cr3+(aq)

A
Pt,H+,Cr2O27(aq),Cr3+(aq)
B
Pt,H+(aq),Cr2O27(aq)
C
Pt,H+,Cr3+(aq)
D
Pt,H2,Cr2O27(aq),Cr3+(aq)
Solution
Verified by Toppr

It is reduction half cell of Cr2O27 and is represented as:
(Pt),H+,Cr2O27(aq),Cr3+(aq)

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