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Updated on : 2022-09-05

Solution

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Correct option is A)

Activity at time $t_{1}$ $R_{1}=λN_{1}$

Activity at time $t_{2}$ $R_{2}=λN_{2}$

Then, the number of atoms disintegrated in time $t_{2}−t_{1}$ is $N_{1}−N_{2}=λR_{1} −λR_{2} $

Half life time period is: $T_{21}=λln2 $

$N_{1}−N_{2}=(R_{1}−R_{2})ln2T $

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