The hardness of a water sample containing $10^{- 3} M {MgSO}_{4}$ expressed as ${CaCO}_{3}$ equivalents (in ppm)is (molar mass of ${MgSO}_{4}$ is $120.37$ $g / mol$ )

Question

The hardness of a water sample containing 10-3-M MgSO-4 expressed as CaCO-3 equivalents -in ppm- is - -molar mass of MgSO-4 is 120-37 g-mol-

Toppr Admin · Accepted Answer

Correct option is A- 100-10-3- molar -MgSO-4 - 10-3- moles of -MgSO-4- present in -1- Litre-n-CaCO-3- -n-MgSO-4- -PPM- -in term of -CaCO-3- - -dfrac-10-3-times 100-1000- -times 10-6-160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- 100- ppm-

The hardness of a water sample containing $$10^{-3}$$M $$MgSO_4$$ expressed as $$CaCO_3$$ equivalents (in ppm) is ________.

[molar mass of $$MgSO_4$$ is $$120.37$$ g/mol]

Correct option is A. 100
$$10^{-3}$$ molar $$MgSO_4 = 10^{-3}$$ moles of $$MgSO_4$$ present in $$1$$ Litre.

$$n_{CaCO_3} =n_{MgSO_4} $$

$$PPM$$ (in term of $$CaCO_3) = \dfrac{10^{-3}\times 100}{1000} \times 10^6$$

$$= 100\ ppm$$

The hardness of a water sample containing $$10^{-3}$$M $$MgSO_4$$ expressed as $$CaCO_3$$ equivalents (in ppm) is ________. [molar mass of $$MgSO_4$$ is $$120.37$$ g/mol]

Correct option is A. 100$$10^{-3}$$ molar $$MgSO_4 = 10^{-3}$$ moles of $$MgSO_4$$ present in $$1$$ Litre.$$n_{CaCO_3} =n_{MgSO_4} $$$$PPM$$ (in term of $$CaCO_3) = \dfrac{10^{-3}\times 100}{1000} \times 10^6$$ $$= 100\ ppm$$

The hardness of a water sample containing $$10^{-3}$$M $$MgSO_4$$ expressed as $$CaCO_3$$ equivalents (in ppm) is ________.

[molar mass of $$MgSO_4$$ is $$120.37$$ g/mol]

Correct option is A. 100
$$10^{-3}$$ molar $$MgSO_4 = 10^{-3}$$ moles of $$MgSO_4$$ present in $$1$$ Litre.

$$n_{CaCO_3} =n_{MgSO_4} $$

$$PPM$$ (in term of $$CaCO_3) = \dfrac{10^{-3}\times 100}{1000} \times 10^6$$

$$= 100\ ppm$$