The height of a cone is 16 cm and its base radius is 12 cm- Find the curved surface area and the total surface area of the cone -Use pi -3-14-

Question

Toppr Admin · Accepted Answer

R-E-F imageOA-16cm-AB-ll-x221A-162-122-x221A-256-144l-20cmcurved surface Area-C-S-A-x3C0-rl-3-14-xD7-12-xD7-20-753-6cm2Total surface Area-T-S-A-x3C0-r-r-l-3-14-xD7-12-12-20-1205-76cm2

The height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone (Use $π = 3.14$ ).

R.E.F image

$O A = 16 c m, A B = l$

$l = \sqrt{16^{2} + 12^{2}} = \sqrt{256 + 144}$

$l = 20 c m$

curved surface Area,

$C . S . A = π r l = 3.14 \times 12 \times 20$ $= 753.6 c m^{2}$

Total surface Area,

$T . S . A = π r (r + l) = 3.14 \times 12 [12 + 20]$ $= 1205.76 c m^{2}$

The height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone (Use π=3.14).

R.E.F imageOA=16cm,AB=ll=√162+122=√256+144l=20cmcurved surface Area,C.S.A=πrl=3.14×12×20=753.6cm2Total surface Area,T.S.A=πr(r+l)=3.14×12[12+20]=1205.76cm2

The height of a cone is 16 cm and its base radius is 12 cm. Find the curved surface area and the total surface area of the cone (Use $π = 3.14$ ).

R.E.F image

$O A = 16 c m, A B = l$

$l = \sqrt{16^{2} + 12^{2}} = \sqrt{256 + 144}$

$l = 20 c m$

curved surface Area,

$C . S . A = π r l = 3.14 \times 12 \times 20$ $= 753.6 c m^{2}$

Total surface Area,

$T . S . A = π r (r + l) = 3.14 \times 12 [12 + 20]$ $= 1205.76 c m^{2}$